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HW5 Q2, 3, 5, 6 (Danny LeBrun)

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3. --What were two early surprising features of exoplanetary systems?      Super Earths are one of the early features of exoplanet systems which are characterized as being between the size of Earth and Neptune. From interstellar observations such as Kepler it's been shown that they are quite common in these systems, yet within our own solar system we don't contain one. We'd vainly expect other systems to be similar to ours, however such is not the case as you can see. Another feature is the existence of Hot Jupiters where Jupiter sized planets orbit very close to their host star and thus cause them to be quite hot. These are found to be common in exoplanetary systems also, however again we do not find one in our own solar system. --What correlation of planet size with occurrence have Kepler results demonstrated?      Kepler showed a correlation between planetary size and abundance. It demonstrated that there are mainly 3 types of planets: Hot and C...

HW 5 Q1 (Danny LeBrun)

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All of it was done on paper so you'll have to look at these picture uploads:

HW 5 Q6 (William Matzko)

6. (a)Usually, the temperature on a planet decreases with altitude. However, in inversion layers, this is not the case. In an inversion layer, temperature increases with altitude. Such a thing is important in the atmosphere of exoplanets because it can give insight into what that planet's atmosphere could be composed of. These inversion layers are usually composed of molecules that absorb UV radiation, so finding these inversion layers on exoplanets is desirable if we want to try and find life on them. (b) We know that P = P_0 exp(-z/H), where P is the pressure, P_0 is the pressure at the surface level, z is the altitude above surface level and H is the scale height. We are given that, on Earth z = 8.8 km and H = 8 km. This corresponds to a pressure of ~0.333*P_0. On a modified planet, to find the z at which we have the same pressure, we first must compute the scale height. We can express the scale height equation as H = k*T/(u*m*g), where k is the Boltzmann constant, T is the te...

HW5 Q4 (William Matzko)

4. Here, we want to make use of the error propagation formula:  σ = [((df/di) σ_i)^2 + ((df/dj) σ_j)^2 + . . .]^(1/2), where  σ is the uncertainty of the quantity we want, f is the function we are differentiating, and i,j are the variables that have the associated uncertainty. Let's start with estimating the error in the radius of the planet, since that equation is easier to work with. The transit depth, g, is simply g = (r/R)^2, where r is the radius of the planet, and R is the radius of the star. We can solve this explicitly for r to give r = g^0.5 R. We assume the transit depth is perfectly known, so our only contributing uncertainty,  σ_R,  comes from the radius of the star. Filling in the error propagation formula, we just take the derivative of r with respect to R: dr/dR = g^0.5. We thus get an uncertainty of our planet to be  σ_p = g^0.5  σ_R. If we have a 10% uncertainty in the radius of the star, then our uncertainty in the planet radius will be 0....

HW5 Q2, Q3, Q5 (William Matzko)

2. We know the phase amplitude is  ε = A*g*(R/r)^2, where A is the geometric albedo, R is the radius of the planet, r = a(1-e^2)/(1+ecos(f)), and g = 10^(-0.4*m). Here, m is just  m = 0.09( α/100) + 2.39( α/100)^2 - 0.65( α/100), where  α is in degrees (the 100's in the denominator are likewise in degrees). We are working with a Venus analog, so we can assume, in this part, that e = 0, so that r = a. The phase amplitude will be maximum when  α = 0. So, our maximum phase amplitude is then  ε = (0.67) (1)(6050km/108E6km)^2, where I have plugged in the geometric albedo of Venus, the radius of Venus, and Venus' semimajor axis. This yeilds  ε = 2E-9.  Now, we are to assume i = 40 degrees and w = 270 degrees. The effect of w is to orient the orbit such that we have a maximum phase angle at f = 0 . We know the relation between  α and these orbital elements: cos( α) = -sin(i)sin(w+f). Plugging in the numbers and solving for  α yields  α = 50 d...

HW5- Heena Chotani

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Question 1- Astrometry Question 2- Exoplanet phase variations Question 3- Exoplanet Demographics a.        The two early surprising features of exoplanetary systems were Super Earths and Hot Jupiters. The reason being that we do not see them in our solar system. b.        Kepler had evidence of planetary radius gap c.        The habitable zone where conditions are for water to exist. Question 4- Question 5- a.          The two properties of a proto-planetary disk that determines what kind of planets that will form are the mass and the temperature of the initial disk b.        There are three types of migration. Type 1 is when the migration of the planet does not affect the proto-planetary disk. This is due to the mass of the planet being too small. The relation between the proto-planetary disk and the planet is...

HW5 Q1 (William Matzko)

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1.  For radial velocities, we have the relation k = 28.4 (m/s) p^-(1/3)(M_p*sin(i)) (M_s)^(-2/3), where M_p is the planet mass in Jupiter masses, and M_s is the mass of the star in solar masses. For astrometry, we have  α  = (M_p/M_s)(a)(d)^(-1), where a is the semimajor axis in AU, and d is the distance to the system in parsecs. Just to make things easier to look at, we can make some simplifying assumptions. We are already told to assume sin(i) = 1 in all instances and M_s is the mass of the Sun. We might as well further assume that our target is one Jupiter mass. Further, we know P is proportional to a ^(3/2). The two above equations then reduce to α = 0.001 (a) (d)^-1 k = 28.4 (m/s) (a)^(-1/2) We are given that astrometry is sensitive to  α = 10 micro arcseconds and above, and radial velocities are sensitive to k = 1 m/s and above. Note that only the astrometry method depends on d. We must now find when the astrometry method becomes more sensitive than the rad...